if you drop an object from a height of 0.8m, it will hit the ground in 0.40s. if you throw a baseball horizontally with an initial speed of 29m/s from the same height, how long will it take the ball to hit the ground
0.40 s
56
To find out how long it takes for the baseball to hit the ground, we need to consider the horizontal and vertical motion of the ball separately.
In vertical motion, since the ball is dropped from a height of 0.8m, we can use the equation of motion for free fall:
h = (1/2) * g * t^2
where:
h = initial vertical height = 0.8m
g = acceleration due to gravity = 9.8m/s^2 (assuming no air resistance)
t = time taken to hit the ground
Simplifying the equation, we get:
0.8 = (1/2) * 9.8 * t^2
Solving for t, we can rearrange the equation and isolate t:
t^2 = (2 * 0.8) / 9.8
t^2 = 0.16 / 9.8
t^2 = 0.01633
t ≈ √(0.01633)
t ≈ 0.1275 seconds
Therefore, when dropped from a height of 0.8m, it takes approximately 0.1275 seconds for the object to hit the ground.
Now, for the baseball thrown horizontally, the vertical motion is the same as when it is dropped because there is no vertical force acting on it after release.
Therefore, the time taken for the baseball to hit the ground when thrown horizontally from a height of 0.8m will also be approximately 0.1275 seconds.