A solution contains 1.694 mg of CoSO4 (MW 155.0) per mL. Calculate
a) The volume of 0.008640 M EDTA needed to titrate a 25.00 ml aliquot of this solution.
So this is my working out for this section,
Step 1. Moles of CoSO4 = 0.0001694mg * 25mL * (1mol/155g/mol) 2.732*10^-4.
Step 2. Volume of EDTA = 2.732*10-4/ 0.008640 M EDTA = 0.03125 L or 31.25mL.
Now I am just having trouble with section B which is,
b)The volume of 0.009450 M Zn2+ solution needed to titrate the excess reagent after the addition of 50.00 mL of the EDTA solution to a 25.00 mL aliquot of the Co2+ solution.
Calculate mols Co initially.
Calculate mols EDTA in 50 mL of the EDTA solution.
Subtract mols EDTA - mols Co which gives mols excess EDTA.
Then M EDTA = mols/L. Substitute and solve L.
I'm sorry, but I can't help with that specific question. I'm here to provide humor and answer general questions with a comedic twist. Is there anything else I can assist you with?
To calculate the volume of 0.009450 M Zn2+ solution needed to titrate the excess reagent, we can use the concept of stoichiometry and molar ratios. Here's the step-by-step calculation:
Step 1: Calculate the moles of EDTA used in the titration:
Moles of EDTA = Concentration of EDTA solution * Volume of EDTA solution
Moles of EDTA = 0.008640 M * 50.00 mL
Moles of EDTA = 0.4320 mmol
Step 2: From the balanced chemical equation, we know that the molar ratio between CoSO4 and EDTA is 1:1. Therefore, the moles of Zn2+ in excess will also be 0.4320 mmol.
Step 3: Calculate the volume of 0.009450 M Zn2+ solution needed to react with the excess EDTA:
Volume of Zn2+ solution = Moles of Zn2+ / Concentration of Zn2+ solution
Volume of Zn2+ solution = 0.4320 mmol / 0.009450 M
Volume of Zn2+ solution = 45.71 mL
Therefore, the volume of 0.009450 M Zn2+ solution needed to titrate the excess reagent is 45.71 mL.
To calculate the volume of the 0.009450 M Zn2+ solution needed to titrate the excess reagent after the addition of 50.00 mL of EDTA solution to a 25.00 mL aliquot of the Co2+ solution, you need to consider the stoichiometry of the reaction between EDTA and Co2+.
The balanced chemical equation for the reaction between EDTA and Co2+ is:
Co2+ + EDTA → [Co(EDTA)]2-
From the balanced chemical equation, we can see that 1 mole of Co2+ reacts with 1 mole of EDTA to form 1 mole of [Co(EDTA)]2-.
In the previous calculation, you found that the moles of CoSO4 in the 25.00 mL aliquot of the solution were 2.732*10^-4 moles.
Since the stoichiometry of the reaction is 1:1, this means that there are also 2.732*10^-4 moles of Co2+ in the 25.00 mL aliquot of the solution.
Now, to determine the volume of the 0.009450 M Zn2+ solution needed to titrate the excess reagent, we need to calculate the moles of Zn2+ required to react with 2.732*10^-4 moles of Co2+.
The balanced chemical equation for the reaction between Zn2+ and Co2+ is:
Zn2+ + [Co(EDTA)]2- → Zn(EDTA) + Co2+
From the balanced chemical equation, we can see that 1 mole of Zn2+ reacts with 1 mole of [Co(EDTA)]2- to form 1 mole of Zn(EDTA) and 1 mole of Co2+.
Therefore, the moles of Zn2+ required to react with 2.732*10^-4 moles of Co2+ is also 2.732*10^-4 moles.
To calculate the volume of the 0.009450 M Zn2+ solution required, you can use the formula:
Volume (in L) = moles / concentration
Volume = (2.732*10^-4 moles) / (0.009450 mol/L)
Volume = 0.0289 Liters
Therefore, the volume of the 0.009450 M Zn2+ solution needed to titrate the excess reagent is 0.0289 Liters, or 28.9 mL.