A fire engine must lift 30 kg of water a vertical distance of 20 m each second. What is the amount of power needed for the water pump for this fire hose?

P=W/t=Fd/t=mgd/t
(30)(9.8)(20)/1= 5880 W
is that right?

yes.

-fire-engine-must-lift-30-kg-of-water-a-vertical-distance-of-20-m-each-second-what-is

Yes, that is correct. The amount of power needed for the water pump for this fire hose is indeed 5880 Watts (W).

To calculate the amount of power needed for the water pump, we can use the formula P = W/t, where P is power, W is work, and t is time.

Now, let's break down the problem step by step:

1. First, let's calculate the work done by the fire engine. The work done (W) is given by the formula W = F * d, where F is the force applied, and d is the distance over which the force is applied.

2. In this case, the force applied is equal to the weight (mg) of the water being lifted. The weight (mg) is given by the mass (m) multiplied by the acceleration due to gravity (g = 9.8 m/s^2).

3. The distance (d) is given as 20 m.

4. Next, we need to determine the time interval (t) over which the work is done. In this case, it is given as 1 second.

5. Now, we can substitute the values into the formula for work: W = (30 kg) * (9.8 m/s^2) * (20 m) = 5880 kg*m^2/s^2.

6. Finally, we can calculate the power by dividing the work (W) by the time (t): P = W/t = 5880 kg*m^2/s^2 / 1 s = 5880 W.

Yes, your calculation is correct! The amount of power needed for the water pump is 5880 watts (W).