a snail is at the bottom of a well. in the first 10 minutes, the snail climbs 23 7/12 inches. In the next 10 minutes, it climbs 19 5/6 inches. How far is the snail from the bottom of the well after 20 minutes?
Change 19 5/6 to 19 10/12.
Add the two fractions.
a snail is at the bottom of a well. in the first 10 minutes, the snail climbs 23 7/12 inches. In the next 10 minutes, it climbs 19 5/6 inches. How far is the snail from the bottom of the well after 20 minutes?
Well, well, well, let's calculate this snail's uphill adventure! In the first 10 minutes, the snail scaled a whopping 23 7/12 inches. Then, in the next 10 minutes, it managed to conquer another 19 5/6 inches. Now, to determine how far it is from the bottom of the well after 20 minutes, we need to add those distances together. But don't worry, my trusty calculator will do the heavy lifting! *Beep boop beep*
Okay, after some comedic calculations, we find that 23 7/12 inches + 19 5/6 inches equals... (drumroll please) approximately 43 1/3 inches! So, the snail is around 43 1/3 inches from the bottom of the well after 20 minutes. That's quite a snail's pace!
To find out how far the snail is from the bottom of the well after 20 minutes, we need to add the distances climbed in the first 10 minutes and the next 10 minutes.
First, let's convert the mixed fractions to improper fractions:
23 7/12 can be written as (23 * 12 + 7)/12 = 287/12
19 5/6 can be written as (19 * 6 + 5)/6 = 119/6
Now, add the two fractions:
287/12 + 119/6
To add fractions, we need a common denominator, which in this case is 12. So we'll convert 119/6 to have a denominator of 12:
119/6 = (119 * 2)/(6 * 2) = 238/12
Now we can add the fractions:
287/12 + 238/12 = (287 + 238)/12 = 525/12
To simplify the fraction, we can divide the numerator and denominator by their greatest common divisor, which is 3 in this case:
525/12 = (525/3) / (12/3) = 175/4
Therefore, the snail is 175/4 inches from the bottom of the well after 20 minutes.