A stone is dropped from the top of a cliff. It hits the ground below after 3.12 s. How high is the cliff?
(in m)
h = (1/2) g t^2 = 4.9 (3.12)^2
To find the height of the cliff, we can use the equation of motion for free fall:
h = (1/2) * g * t^2
Where:
h is the height of the cliff,
g is the acceleration due to gravity (approximately 9.8 m/s^2), and
t is the time taken for the stone to hit the ground (3.12 s in this case).
Substituting the given values into the equation, we get:
h = (1/2) * 9.8 * (3.12)^2
h = 15.232 m
Therefore, the height of the cliff is approximately 15.232 meters.