Iron 3 hydroxide reacts with acetic acid to form iron 3 acetate and water. If 45.4g of water are formed,what mass of iron 3 acetate will be produced?
•Fe(OH)3+3HC2H3O2--->Fe(C2H3O2)+3H2O
45.4H2O( ? Fe(C2H3O))
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( ? H2O)
45.4g of H2O*(1 mole/18.00g)=moles of H2O
moles of H2O*(moles of Fe(C2H3O2)/3 mole of H2O)=moles of Fe(C2H3O2)
moles of Fe(C2H3O2)*(232.98 g/1 mole of moles of Fe(C2H3O2))= g of Fe(C2H3O2)
You made a typo on the formula for iron (III) acetate.
•Fe(OH)3 + 3HC2H3O2 --> Fe(C2H3O2)3 + 3H2O
mols water formed = grams/molar mass = ?
Convert to mols iron(III) acetate using the coefficients in the balanced equation. That will be
? mols H2O x (1 mol Fe(Ac)3/3 mol H2O) = ?mols H2O x 1/3 = x mols Fe(Ac)3.
Then convert that to grams. g = mols x molar mass = ?
To determine the mass of iron (III) acetate produced, we can start by using the balanced chemical equation:
Fe(OH)3 + 3HC2H3O2 → Fe(C2H3O2)3 + 3H2O
We know that 45.4g of water (H2O) are formed in the reaction.
From the balanced equation, we can see that the molar ratio between water and iron (III) acetate is 3:1. This means that for every 3 moles of water produced, 1 mole of iron (III) acetate is formed.
1 mole of water (H2O) has a molar mass of approximately 18 g/mol.
To find the moles of water produced, we can divide the mass of water by its molar mass:
45.4g H2O / 18 g/mol = 2.52 moles of H2O.
Since the molar ratio between water and iron (III) acetate is 3:1, the moles of iron (III) acetate produced will be 1/3 of the moles of water produced.
Moles of iron (III) acetate = 2.52 moles of H2O / 3 = 0.84 moles of Fe(C2H3O2)3.
Now, we need to find the molar mass of iron (III) acetate (Fe(C2H3O2)3). By looking at the elements in the compound, we can calculate its molar mass:
Iron (Fe): 55.85 g/mol
Carbon (C): 12.01 g/mol
Hydrogen (H): 1.01 g/mol
Oxygen (O): 16.00 g/mol
Molar mass of iron (III) acetate (Fe(C2H3O2)3):
Fe: 55.85 g/mol
(C2H3O2)3: (12.01 g/mol x 2 + 1.01 g/mol x 3 + 16.00 g/mol x 2) x 3 = 228.24 g/mol
The molar mass of Fe(C2H3O2)3 is 55.85 g/mol + 228.24 g/mol = 284.09 g/mol.
Finally, we can find the mass of iron (III) acetate produced by multiplying the moles of iron (III) acetate by its molar mass:
Mass of Fe(C2H3O2)3 = 0.84 moles x 284.09 g/mol = 238.73 g.
Therefore, the mass of iron (III) acetate produced in this reaction is approximately 238.73 grams.
To find the mass of iron 3 acetate produced, we need to use the given information about the mass of water formed in the reaction.
Step 1: Determine the molar mass of water (H2O).
The molar mass of water is the sum of the molar masses of its constituent elements: hydrogen (H) and oxygen (O).
Molar mass of H = 1.008 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of H2O = (2 * molar mass of H) + molar mass of O
= (2 * 1.008 g/mol) + 16.00 g/mol
= 18.016 g/mol
Step 2: Convert the given mass of water (45.4 g) to moles.
To convert the mass of water to moles, divide the given mass by the molar mass of water.
Moles of H2O = mass of H2O / molar mass of H2O
= 45.4 g / 18.016 g/mol
≈ 2.52 mol
Step 3: Use the balanced equation to determine the mole ratio between water (H2O) and iron 3 acetate (Fe(C2H3O)3).
From the balanced equation: Fe(OH)3 + 3 HC2H3O2 -> Fe(C2H3O)3 + 3 H2O
The mole ratio between H2O and Fe(C2H3O)3 is 1:1.
This means for every 1 mole of water, 1 mole of iron 3 acetate is produced.
Step 4: Convert moles of H2O to moles of Fe(C2H3O)3.
Since the mole ratio is 1:1, the moles of H2O is equal to the moles of Fe(C2H3O)3.
Moles of Fe(C2H3O)3 = moles of H2O
= 2.52 mol
Step 5: Determine the molar mass of Fe(C2H3O)3.
The molar mass of Fe(C2H3O)3 can be calculated by summing the molar masses of its constituent elements: iron (Fe), carbon (C), hydrogen (H), and oxygen (O).
Molar mass of Fe = 55.845 g/mol
Molar mass of C = 12.01 g/mol
Molar mass of H = 1.008 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of Fe(C2H3O)3 = (molar mass of Fe) + (3 * molar mass of C) + (9 * molar mass of H) + (6 * molar mass of O)
= 55.845 g/mol + (3 * 12.01 g/mol) + (9 * 1.008 g/mol) + (6 * 16.00 g/mol)
≈ 167.87 g/mol
Step 6: Convert moles of Fe(C2H3O)3 to mass.
To convert the moles of Fe(C2H3O)3 to mass, multiply the moles by the molar mass of Fe(C2H3O)3.
Mass of Fe(C2H3O)3 = moles of Fe(C2H3O)3 * molar mass of Fe(C2H3O)3
= 2.52 mol * 167.87 g/mol
≈ 423.47 g
Therefore, approximately 423.47 grams of iron 3 acetate will be produced when 45.4 grams of water are formed in this reaction.