An automobile travels a distance of 12 km in 4 minutes. It then moves the next 12 km in 2 minutes. Please help me to calculate its acceleration which is constant throughout the motion. Thanks in advance ))))
average velocity first=12/4 = 3km/min
average velocity second= 12/2=6km/min
accelaration=change velocity/time =3km/min /(6m)= .5 km/min^2
To calculate the acceleration of the automobile, we can use the equation:
Acceleration = (Final velocity - Initial velocity) / Time
First, let's find the initial velocity for the first 4 minutes:
Initial velocity = Distance / Time = 12 km / 4 min = 3 km/min
Next, let's find the final velocity for the first 4 minutes. Since we know the distance and time, we can rearrange the equation to solve for the final velocity:
Final velocity = Distance / Time = 12 km / 4 min = 3 km/min
Now, let's find the initial velocity for the next 2 minutes:
Initial velocity = Distance / Time = 12 km / 2 min = 6 km/min
Next, let's find the final velocity for the next 2 minutes. Since we know the distance and time, we can rearrange the equation to solve for the final velocity:
Final velocity = Distance / Time = 12 km / 2 min = 6 km/min
Now we have all the necessary values to calculate the acceleration for each segment of motion:
For the first 4 minutes:
Acceleration = (Final velocity - Initial velocity) / Time
Acceleration = (3 km/min - 3 km/min) / 4 min
Acceleration = (0 km/min) / 4 min
Acceleration = 0 km/min²
For the next 2 minutes:
Acceleration = (Final velocity - Initial velocity) / Time
Acceleration = (6 km/min - 3 km/min) / 2 min
Acceleration = (3 km/min) / 2 min
Acceleration = 1.5 km/min²
Therefore, the acceleration of the automobile is 0 km/min² for the first 4 minutes and 1.5 km/min² for the next 2 minutes.