Kelly and Sally both set off at 8 :30 am for Town P, 180 km away. Sally arrived at 100:30 am, ahead of Kelly. If Kelly traveled at a speed which was 10 km/h slower than Sally, the Kelly would have arrived in Town P at ________ PM.
it took Sally 2 hours to go 180 km.
That's 90 km/hr.
If Kelley traveled at 80 km/hr, it would take her 2.25 hr.
So, she would arrive at 10:45 am
To find out when Kelly would have arrived in Town P, we need to calculate Sally's travel time first.
The distance between the two towns is 180 km, and Sally arrived at 10:30 am, which means she took (10:30 am - 8:30 am) = 2 hours to reach Town P.
Now, we know that Kelly traveled at a speed 10 km/h slower than Sally. Let's assume Sally's speed was S km/h, so Kelly's speed would be (S - 10) km/h.
We can use the formula: Time = Distance / Speed to find out Kelly's travel time.
So, Kelly's travel time can be represented as: (180 km) / (S - 10) km/h.
Since Sally took 2 hours to reach Town P, we know that Kelly was slower and thus would have taken longer than 2 hours. Let's assume Kelly's travel time was T hours.
Therefore, we can write the equation: T = (180 km) / (S - 10) km/h.
We can solve this equation for T:
T = (180 km) / (S - 10) km/h
T(S - 10) = 180 km
TS - 10T = 180 km
TS = 180 km + 10T
TS = 10T + 180
TS - 10T = 180
Now we can use this equation to find the value of T (Kelly's travel time).
However, without knowing the value of S (Sally's speed), we cannot calculate the exact time. Please provide the value of Sally's speed in km/h, and I can help you find the answer.