Please someone should help me with this.

An elastic material has a length of 36cm when a load of 40N is hung on it and a length of 45cm when a load of 60N is hung on it. The original length of the string is ?

using youngs modules from hookes law that is strain. e/l, where e=length of material - initial length/original length 45-36=l l=9

To find the original length of the string, we can use the concept of Hooke's Law. Hooke's Law states that the extension of an elastic material is directly proportional to the applied force.

Let's denote the original length of the string as "L". We are given two scenarios:

1. When a load of 40N is hung on the string, its length is 36cm.
2. When a load of 60N is hung on the string, its length is 45cm.

Using Hooke's Law, we can set up two equations:

1. L + x = 36cm
Where "x" is the extension of the string when a load of 40N is applied.

2. L + y = 45cm
Where "y" is the extension of the string when a load of 60N is applied.

Now, we need to find the values of "x" and "y" to solve for the original length "L". We can do this by subtracting the original lengths from the given lengths:

1. x = 36cm - L
2. y = 45cm - L

Substituting these values back into the equations, we get:

1. L + (36cm - L) = 36cm
36cm = 2L
L = 18cm

2. L + (45cm - L) = 45cm
45cm = 2L
L = 22.5cm

Since these two equations produce different values for the original length "L" (18cm and 22.5cm), there seems to be an error or inconsistency in the given information or measurements. Please recheck your question or provide additional information if necessary.