ALuminum can be determined gravimetricaly by the reaction with solution of 8-hydroxyquinoline (C9H7NO3).The net ionic equation . A mass of 0.1248g of Al(C9H6NO)3 WAS obtained by precipitating all of the the Al3+ from a solution prepared by dissolving 1.8571g of a mineral. what is the mass percent of alumininum in the mineral sample
Now, for every mole of Al(C9H6NO)3, there is 1 mole of Al^3+. i.e., 1 mole of Al=1 mole of Al(C9H6NO)3
Al(C9H6NO)3 *(1 mole/459.4317 g)= moles of Al(C9H6NO)3
moles of Al(C9H6NO)3=moles of Al^3+
moles of Al^3+*(26.98g/1 mole)= mass of Al^3+ in grams
(mass of Al^3+ in grams/1.8571g)*100=mass percent of Al^3+ in the mineral sample
***Answer contains no more and no less than four significant figures.
@@Look for correction.
Now, for every mole of Al(C9H6NO)3, there is 1 mole of Al^3+. i.e., 1 mole of Al=1 mole of Al(C9H6NO)3
@@0.1248g of Al(C9H6NO)3 *(1 mole/459.4317 g)= moles of Al(C9H6NO)3
moles of Al(C9H6NO)3=moles of Al^3+
moles of Al^3+*(26.98g/1 mole)= mass of Al^3+ in grams
(mass of Al^3+ in grams/1.8571g)*100=mass percent of Al^3+ in the mineral sample
***Answer contains no more and no less than four significant figures.
To find the mass percent of aluminum in the mineral sample, we need to calculate the mass of aluminum in the compound Al(C9H6NO)3 and then use that to determine the mass percent.
1. Calculate the molar mass of Al(C9H6NO)3:
- Aluminum (Al) has a molar mass of 26.98 g/mol.
- 8-Hydroxyquinoline (C9H7NO3) has a molar mass of 173.16 g/mol.
- So, the molar mass of Al(C9H6NO)3 = (26.98 g/mol) + 3 * (173.16 g/mol) = 546.62 g/mol.
2. Calculate the moles of Al(C9H6NO)3 obtained:
- Given mass of Al(C9H6NO)3 = 0.1248 g.
- Moles = Mass / Molar mass = 0.1248 g / 546.62 g/mol ≈ 0.000228 moles.
3. Determine the moles of Al3+ ions in Al(C9H6NO)3:
- 1 mole of Al(C9H6NO)3 gives 1 mole of Al3+ ions.
- So, the moles of Al3+ ions = 0.000228 moles.
4. Calculate the moles of Al3+ ions in the mineral sample:
- Since 1.8571 g of the mineral sample gave 0.1248 g of Al(C9H6NO)3, we can assume that all the aluminum in the mineral has reacted to form Al(C9H6NO)3.
- Moles of Al3+ ions in the mineral sample = Moles in Al(C9H6NO)3 = 0.000228 moles.
5. Calculate the mass of aluminum in the mineral sample:
- Molar mass of aluminum = 26.98 g/mol.
- Mass = Moles * Molar mass = 0.000228 moles * 26.98 g/mol ≈ 0.00617 g.
6. Calculate the mass percent of aluminum in the mineral sample:
- Mass percent = (Mass of aluminum / Mass of mineral sample) * 100.
= (0.00617 g / 1.8571 g) * 100 ≈ 0.33%.
Therefore, the mass percent of aluminum in the mineral sample is approximately 0.33%.
To calculate the mass percent of aluminum in the mineral sample, we need to use the following steps:
1. Determine the moles of Al(C9H6NO)3:
- The molar mass of Al(C9H6NO)3 can be calculated by adding the masses of each element:
Molar mass of Al = 26.98 g/mol
Molar mass of C9H6NO = (12.01 * 9) + (1.01 * 6) + (14.01 * 1) + (16.00 * 1) = 159.17 g/mol
Molar mass of Al(C9H6NO)3 = (26.98 * 1) + (159.17 * 3) = 505.49 g/mol
- Use the given mass of Al(C9H6NO)3 (0.1248 g) and its molar mass to calculate the moles:
Moles of Al(C9H6NO)3 = mass / molar mass = 0.1248 g / 505.49 g/mol = 0.0002468 mol
2. Determine the moles of Al3+:
- Based on the stoichiometry of the reaction, each mole of Al(C9H6NO)3 corresponds to one mole of Al3+.
- Therefore, the moles of Al3+ is also 0.0002468 mol.
3. Determine the moles of Aluminum in the mineral sample:
- Since each molecule of Al(C9H6NO)3 contains one Aluminum ion (Al3+), the moles of aluminum in the mineral sample is also 0.0002468 mol.
4. Determine the mass of Aluminum in the mineral sample:
- Since the molar mass of Aluminum is 26.98 g/mol, we can calculate the mass of Aluminum:
Mass of Aluminum = moles of Aluminum * molar mass of Aluminum = 0.0002468 mol * 26.98 g/mol = 0.006653 g
5. Determine the mass percent of Aluminum in the mineral sample:
- The mass percent is calculated as (mass of Aluminum / mass of mineral sample) * 100%.
Mass percent of Aluminum = (0.006653 g / 1.8571 g) * 100% ≈ 0.358%
Therefore, the mass percent of aluminum in the mineral sample is approximately 0.358%.