A ball is thrown at 22 m/s at 45 degrees to the horizontal. A 5 foot tall fence is located 100 meters away. Does
the ball make it over the fence?
You can use the range equation to figure this out, first, if the ball even makes it to 100m.
horizontal distance=R=Vi^2*Sin2(Theta)/g
Where
Vi=22m/s
Theta=45
and
g=9.8m/s^2
Solve for R:
R=(22m/s)^2*Sin2(45)/(9.8m/s^2)
R=(22m/s)^2*Sin2(45)/(9.8m/s^2)
R=49.39m
The ball doesn't make it that far.