A 5.0 L sample of nitrogen gas has a pressure of 95 kpa. What is the final volume of the gas if the pressure is tripled?
I know p1 = 95, v1=5.0 and p2 = tripled
What i don't understand is what number is tripled, is it 95 times 3??
P1 V1 = P2 V2
P2 = 3 P1
P1 V1 = 3 P1 V2
so
V2 = V1/3 = 5/3 liters
Damon showed you how to work the problem a short way. The answer to your question is yes, it is 3*95 = ?
To determine the final volume of the gas when the pressure is tripled, you need to use Boyle's Law. Boyle's Law states that the pressure and volume of a gas are inversely proportional when the temperature and the number of particles are kept constant.
Boyle's Law can be expressed as follows:
P1 × V1 = P2 × V2
Where:
P1 = initial pressure
V1 = initial volume
P2 = final pressure
V2 = final volume
In this case, you are given that the initial pressure (P1) is 95 kPa and the initial volume (V1) is 5.0 L. The final pressure (P2) is tripled, which means it would be three times the initial pressure. So, P2 = 3 × P1.
Now you can plug the given values into the formula and solve for V2:
P1 × V1 = P2 × V2
95 kPa × 5.0 L = (3 × 95 kPa) × V2
To solve for V2, divide both sides of the equation by (3 × 95 kPa):
V2 = (95 kPa × 5.0 L) / (3 × 95 kPa)
Simplify the equation:
V2 = (5.0 L) / 3
So, the final volume of the gas when the pressure is tripled is approximately 1.67 L.