the length of a rectangular mirror is 12 cm longer than its width. find its dimensional if its perimeter is 60cm.
with solution pls...
The length of a rectangular mirror is 12 cm longer than its width.find its dimension if its perimeter is 60 cm.
To solve this problem, we can use algebraic expressions and equations. Let's represent the width of the mirror as 'w' (in cm). According to the problem, the length is 12 cm longer than the width, so we can represent the length as 'w + 12' (in cm).
The formula for the perimeter of a rectangle is given by P = 2L + 2W, where L is the length and W is the width. In this case, we know the perimeter is 60 cm. Substituting the values, we have:
60 = 2(w + 12) + 2w
Now, let's solve this equation to find the width:
60 = 2w + 24 + 2w
60 = 4w + 24
60 - 24 = 4w
36 = 4w
w = 36/4
w = 9 cm
Now that we have the width, we can substitute this value back into our expression for the length:
Length = Width + 12
Length = 9 + 12
Length = 21 cm
Therefore, the dimensions of the rectangular mirror are width = 9 cm and length = 21 cm.
width --- x
length --- x+12
perimeter = 2xwidth + 2xlength
2x + 2(x+12) = 60
etc
should be easy