A skillet made of Iron (Fe) weighing 1.8 kg is heated on a stove to a temperature of 202 degrees C. If the skillet is removed from the stove and allowed to cool to room temperature (21 degrees C), how much heat must be removed from the skillet. The specific heat of Iron is 0.449 J/(g. degrees C).
q = heat removed = mass Fe x specific heat Fe x (Tfinal-Tinitial)
To calculate the heat that must be removed from the skillet, we can use the equation:
Q = m × c × ΔT
where:
Q is the heat transferred,
m is the mass of the skillet,
c is the specific heat of iron, and
ΔT is the change in temperature.
First, we need to convert the mass of the skillet to grams:
1.8 kg × 1000 g/kg = 1800 g
Next, we calculate the change in temperature:
ΔT = Tfinal - Tinitial
ΔT = 21°C - 202°C
ΔT = -181°C
Now we can substitute the values into the equation:
Q = 1800 g × 0.449 J/(g.°C) × (-181°C)
Simplifying the equation, we get:
Q = - 145,381.8 J
Therefore, approximately 145,381.8 Joules of heat must be removed from the skillet.