A 0.248 M ZnCO3 solution is made from 21.4 g of solute? What is the volume of the solution?
mols ZnCO3 = grams/molar mass
Then M = mols/L solution You know M and mols, solve for L.
To find the volume of the solution, we need to use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
First, we need to convert the given mass of solute (21.4 g) into moles. To do this, we will use the molar mass of ZnCO3.
The molar mass of ZnCO3 can be calculated by adding up the atomic masses of its constituent elements:
Zn = 65.38 g/mol
C = 12.01 g/mol
O = 16.00 g/mol (We have three oxygen atoms, so we multiply this by 3)
Total molar mass = (65.38 + 12.01 + (16.00 × 3)) g/mol = 125.38 g/mol
Now, we can calculate the number of moles using the given mass of solute:
moles = mass / molar mass = 21.4 g / 125.38 g/mol
Next, we need to convert the molarity from moles to liters. Since Molarity (M) is expressed as moles/liter, we rearrange the formula to solve for volume:
Volume (in liters) = moles of solute / Molarity
We substitute the given values into the formula:
Volume = (21.4 g / 125.38 g/mol) / 0.248 mol/L
We perform the calculation to find the volume of the solution:
Volume = 0.169 L
Therefore, the volume of the 0.248 M ZnCO3 solution made from 21.4 g of solute is 0.169 liters.