suppose a car is decelerating at a constant rate of 5 m/s^2 (i.e. its acceleration is -5m/s^2) . If the car has an initial velocity of 25m/s, how far does the car travel before coming to a full stop?
To find how far the car travels before coming to a complete stop, we need to use the equation of motion:
s = (v^2 - u^2) / (2a)
where:
s = distance traveled
v = final velocity (0 m/s since the car comes to a stop)
u = initial velocity (25 m/s)
a = acceleration (-5 m/s^2)
Now let's substitute the values into the equation and solve:
s = (0^2 - 25^2) / (2 * -5)
s = (0 - 625) / (-10)
s = -625 / -10
s = 62.5 meters
Therefore, the car travels 62.5 meters before coming to a full stop.