In an acid base titration,25.0 ml of nitric acid, HNO3, were neautralized by 28.0 mL of 0.209 mol/L calcium hydroxide, Ca(OH)2. What is the concentration of the nitric acid?
2HNO3 + Ca(OH)2 ==> Ca(NO3)2 + 2H2O
mols Ca(OH)2 = M x l = ?
mols HNO3 = twice mols Ca(OH)2 [Note the coefficients in the balanced equation]
M HNO3 = mols HNO3/L HNO3 = ?
What does M x l
I know M is the molar mass, but what is the l you wrote
M is the molarity. L is liters. I should have used the cap L and not the lower case l. There is no accepted abbreviation for molar mass.
To find the concentration of nitric acid, we can use the concept of stoichiometry and the balanced equation for the neutralization reaction. The balanced equation for the reaction between nitric acid (HNO3) and calcium hydroxide (Ca(OH)2) is:
2HNO3 + Ca(OH)2 → Ca(NO3)2 + 2H2O
From the balanced equation, we can see that one mole of nitric acid reacts with one mole of calcium hydroxide. Therefore, the ratio of moles between nitric acid and calcium hydroxide is 1:1.
Given that the volume of calcium hydroxide solution used is 28.0 mL and its concentration is 0.209 mol/L, we can calculate the number of moles of calcium hydroxide used as follows:
Number of moles of calcium hydroxide = concentration * volume
= 0.209 mol/L * 0.028 L
= 0.005852 mol
Since the stoichiometric ratio between HNO3 and Ca(OH)2 is 1:1, the number of moles of nitric acid used is also 0.005852 mol.
Now, we can calculate the concentration of nitric acid using the volume of nitric acid solution used, which is 25.0 mL.
Concentration of nitric acid = moles of nitric acid / volume of nitric acid
= 0.005852 mol / 0.025 L
= 0.234 mol/L
Therefore, the concentration of nitric acid (HNO3) is 0.234 mol/L.