The linear impulse delivered by the hit of a

boxer is 222 N · s during the 0.187 s of contact.
What is the magnitude of the average force
exerted on the glove by the other boxer?
Answer in units of N.

To find the magnitude of the average force exerted on the glove by the other boxer, we can use Newton's second law, which states that the force exerted on an object is equal to the rate of change of its momentum.

The linear impulse delivered by the hit of the boxer is given as 222 N · s. Impulse is defined as the change in momentum of an object, and can be calculated using the formula:

Impulse = Force × Time

In this case, we are given the impulse and the time of contact, so we can rearrange the formula to solve for the force:

Force = Impulse / Time

Plugging in the values, we have:

Force = 222 N · s / 0.187 s

Calculating the division, we get:

Force ≈ 1189.84 N

Therefore, the magnitude of the average force exerted on the glove by the other boxer is approximately 1189.84 N.