What volume of 0.20M NaOH will contain 1.00g of NaOH
mol of Na O H = 23+16 + 1 = 40 grams
so 1 gram is 1/40 mol = .025 mol
.025 mol = .2 mol/liter * x liters
so
x = .025/.2 = .125 liters or 1/8 liter
or 125 mL.
To calculate the volume of 0.20M NaOH solution that contains 1.00g of NaOH, you need to use the equation:
moles = mass / molar mass
First, you need to calculate the number of moles of NaOH using the given mass of NaOH. The molar mass of NaOH is 22.99g/mol + 16g/mol + 1.01g/mol = 39.99g/mol.
moles = 1.00g / 39.99g/mol ≈ 0.025 moles
Next, you can use the equation:
moles = Molarity x Volume
Rearranging the equation, you get:
Volume = moles / Molarity
Substituting the given values:
Volume = 0.025 moles / 0.20 moles/L ≈ 0.125 L
Therefore, the volume of 0.20M NaOH solution that contains 1.00g of NaOH is approximately 0.125 liters (or 125 mL).