A runner travelling at a velocity of 2.5 m/s[S] accelerates at a constant rate to pass another
runner to win the race. She accelerates at a steady 1.5 m/s2
for 4.0 s and wins the race.
(a) How fast was she running at the end of the race?
V = Vo + a*t
Vo = 2.5 m/s.
a = 1.5 m/s^2
t = 4 s.
Solve for V(m/s).
To find out how fast the runner was running at the end of the race, we need to use the equation of motion:
vf = vi + at
Where:
- vf represents the final velocity of the runner
- vi represents the initial velocity of the runner
- a represents the acceleration
- t represents the time of acceleration
Given:
- The initial velocity of the runner (vi) is 2.5 m/s[S]
- The acceleration (a) is 1.5 m/s^2
- The time of acceleration (t) is 4.0 s
Now, let's substitute the given values into the equation of motion:
vf = vi + at
vf = 2.5 m/s[S] + (1.5 m/s^2)(4.0 s)
vf = 2.5 m/s[S] + 6.0 m/s
vf = 8.5 m/s
Therefore, the runner was running at a speed of 8.5 m/s at the end of the race.