A racing car has a mass of 1970 kg.
The acceleration of gravity is 9.8 m/s^2.
What is its kinetic energy if it has a speed
of 102 km/h?
Answer in units of J.
M = 1970 kg
V = 102km/h = 102,000m/3600s. = 28.33 m/s.
KE = 0.5*M*V^2
Why did the racing car bring a calculator to the track? Because it wanted to calculate its kinetic energy, of course! Let's help it out.
First, let's convert the speed from km/h to meters per second (m/s). To do that, we divide the speed by 3.6 (since 1 km/h is equal to 1/3.6 m/s).
102 km/h / 3.6 = 28.333... m/s (rounded to 3 decimal places)
Now, to calculate the kinetic energy, we use the formula:
Kinetic energy = (1/2) * mass * (velocity)^2
Plugging in the values:
Kinetic energy = (1/2) * 1970 kg * (28.333 m/s)^2
Calculating:
Kinetic energy ≈ 1,987,604.86 J
So, the kinetic energy of the racing car is approximately 1,987,604.86 joules.
To find the kinetic energy of the racing car, we can use the formula:
Kinetic energy (KE) = (1/2) * mass * velocity^2
Step 1: Convert the speed from km/h to m/s.
Given speed = 102 km/h
To convert km/h to m/s, we multiply by 1000 (since there are 1000 meters in a kilometer) and divide by 3600 (since there are 3600 seconds in an hour).
Speed in m/s = (102 km/h) * (1000 m/km) / (3600 s/h)
Step 2: Calculate the kinetic energy using the formula.
Given mass = 1970 kg
Speed in m/s = (102,000 m/3600 s) = 28.33 m/s (rounded to two decimal places)
Kinetic energy (KE) = (1/2) * mass * velocity^2
KE = (1/2) * 1970 kg * (28.33 m/s)^2
Step 3: Calculate the kinetic energy.
Let's plug in the values into the formula:
KE = (1/2) * 1970 kg * (28.33 m/s)^2
KE ≈ 2521104.352 J
Thus, the kinetic energy of the racing car is approximately 2521104.352 J.
To calculate the kinetic energy of the racing car, we can use the equation:
Kinetic Energy (KE) = 1/2 * mass * velocity^2
First, we need to convert the speed from km/h to m/s. We know that 1 km = 1000 m and 1 h = 3600 s. Therefore,
102 km/h = (102 * 1000) / 3600 m/s ≈ 28.33 m/s
Now, we can substitute the values into the equation:
KE = 1/2 * mass * velocity^2
= 1/2 * 1970 kg * (28.33 m/s)^2
= 1/2 * 1970 kg * 803.3489 m^2/s^2
≈ 788,913.61 J
So, the kinetic energy of the racing car is approximately 788,913.61 J (joules).