The base of an isoceles triangle is 26 cm .If the perimeter is 72 cm.
Find the lengt of each of the equal sides
x+x+26 = 72
carry on
To find the length of each of the equal sides of an isosceles triangle, we need to understand a few properties of this type of triangle.
In an isosceles triangle, there are two equal sides. The base is the remaining side. The sum of the lengths of any two sides of a triangle is always greater than the length of the third side.
In this problem, we are given the base length of 26 cm and the perimeter of the triangle, which is 72 cm.
Let's denote the length of each equal side as 'x'.
We can set up the following equation to solve for 'x':
Perimeter = Sum of the lengths of all three sides
72 cm = x + x + 26 cm
Simplifying this equation, we have:
72 cm = 2x + 26 cm
Subtracting 26 cm from both sides, we get:
72 cm - 26 cm = 2x
46 cm = 2x
Dividing both sides by 2, we find:
23 cm = x
So, the length of each of the equal sides of the isosceles triangle is 23 cm.