For each reaction, write the chemical formulae of the oxidized reactants in the space provided. Write the chemical formulae of the reduced reactants in the space provided.
2AgNO3 + Cu -> 2Ag + Cu(NO3)2
Reduced:Cu->Cu+ +1e-
Oxidized: Ag+ + 1e- -> Ag
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Oxidation is the loss of electrons. Cu goes from zero on the left to 2+ on the right. Cu ==> Cu^2+ + 2e
Reduction is the gain of electrons. Ag goes from +1 on the left to zero on the right.
Ag^+ + e ==> Ag
To determine the chemical formulae of the oxidized and reduced reactants in the given reaction, we need to analyze the changes in oxidation states of the elements involved.
In the reaction 2AgNO3 + Cu -> 2Ag + Cu(NO3)2, the copper (Cu) atoms are being oxidized and the silver (Ag) atoms are being reduced.
To find the chemical formula of the oxidized reactant (Cu), we need to identify the copper atom in its oxidized form. We can see that copper (Cu) is being oxidized because its oxidation state changes from 0 to +2, which means it has lost two electrons. Therefore, we write the formula for the oxidized reactant as Cu.
To find the chemical formula of the reduced reactant (Ag), we need to identify the silver atom in its reduced form. We can see that silver (Ag) is being reduced because its oxidation state changes from +1 to 0, which means it has gained one electron. Therefore, we write the formula for the reduced reactant as Ag+.
So, the chemical formulae of the oxidized and reduced reactants in the given reaction are as follows:
Oxidized reactant: Cu
Reduced reactant: Ag
The chemical formulae of the oxidized reactants and reduced reactants in the given reaction are as follows:
Oxidized reactant: AgNO3
Reduced reactant: Cu