An 80.00 kg man playing hockey catches a puck moving at 20 m/s. The man is initially at rest. The man and puck move together after the collision. The puck's mass is 0.16 kg. What is the final velocity?
A. 13.6 m/s
B. 0.04 m/s
C. 1.36 m/s
D. 4.0 m/s
(M1+M2)V = M2*V2
80.16V = 0.16*20
Solve for V.
0.04 m/s
Correct!
To find the final velocity of the man and puck after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision should equal the total momentum after the collision.
The momentum of an object can be calculated by multiplying its mass with its velocity. So, before the collision, the momentum of the man is 0 kg*m/s (since he is initially at rest), and the momentum of the puck is (0.16 kg) * (20 m/s) = 3.2 kg*m/s.
After the collision, the man and the puck move together with the same final velocity. Let's express their combined mass as the sum of their individual masses, which is 80.16 kg. So their total momentum after the collision is (80.16 kg) * (final velocity) = 80.16 kg*m/s * final velocity.
Since momentum is conserved, we can set the initial momentum equal to the final momentum:
0 kg*m/s + 3.2 kg*m/s = 80.16 kg*m/s * final velocity
Simplifying the equation:
3.2 kg*m/s = 80.16 kg*m/s * final velocity
Dividing both sides of the equation by 80.16 kg*m/s:
final velocity = 3.2 kg*m/s / 80.16 kg*m/s
final velocity ≈ 0.04 m/s
So the final velocity of the man and the puck after the collision is approximately 0.04 m/s.
Therefore, the correct answer is B. 0.04 m/s.