5000J of heat is supplied to 10kg of water at 30degrees. What will be the water's final temperature

To find the final temperature of the water, we need to use the equation:

Q = m * c * ΔT

Where:
Q is the heat supplied to the water (in this case, 5000J),
m is the mass of water (10kg),
c is the specific heat capacity of water (approximately 4186 J/kg°C), and
ΔT is the change in temperature.

We can rearrange the equation to solve for ΔT:

ΔT = Q / (m * c)

Let's substitute the values into the equation:

ΔT = 5000J / (10kg * 4186 J/kg°C)

Calculating this, we find:

ΔT ≈ 0.1196 °C

Now, to find the final temperature:

Final temperature = Initial temperature + ΔT

Given that the initial temperature is 30°C, we can calculate the final temperature:

Final temperature ≈ 30°C + 0.1196°C

Therefore, the water's final temperature will be approximately 30.12°C.

(T-30)(10 kg) (heat capacity of water) = 5000