Sheila has 7y craft sticks. Mark has 4y fewer craft sticks then Sheila and y craft sticks more than Linda. Then Sheila gave 2y craft sticks to Mark and Linda. How many craft sticks in terms of y did Mark and Linda have in the end?
If mark had 6 more craft sticks than Linda at first how many many craft sticks would mark and Linda have in the end?
Oops! Posted pre-maturely.
2. Mark: 3y
Linda: 3y - 6
In the end:
Mark: 3y + 2y = 5y
Linda: (3y-6) + 2y = 5y - 6
1. Sheila: 7y Craft sticks.
Mark: 7y-4y = 3y
Linda: 3y-y = 2y
In the end:
Sheila: 7y-2y-2y = 3y
Mark: 3y + 2y = 5y
Linda: 2y + 2y = 4y
2. Mark: 3y
Linda: 3y - 6
To solve the first question regarding the number of craft sticks Mark and Linda had in the end, let's break it down step by step:
1. Sheila has 7y craft sticks.
2. Mark has 4y fewer craft sticks than Sheila, so Mark has (7y - 4y) = 3y craft sticks.
3. Mark also has y craft sticks more than Linda, so Linda has (3y - y) = 2y craft sticks.
4. Sheila gave 2y craft sticks to both Mark and Linda. After giving away, Sheila has (7y - 2y) = 5y craft sticks remaining.
5. Mark receives 2y craft sticks, so his final count becomes (3y + 2y) = 5y craft sticks.
6. Linda also receives 2y craft sticks, so her final count becomes (2y + 2y) = 4y craft sticks.
Therefore, in the end, Mark has 5y craft sticks, and Linda has 4y craft sticks.
For the second question, let's assume Mark had 6 more craft sticks than Linda originally. Starting from step 3 above:
3. Mark has 6 more craft sticks than Linda, so Linda has x craft sticks.
4. Sheila gave 2y craft sticks to both Mark and Linda. After giving away, Sheila has 5y craft sticks remaining.
5. Mark receives 2y craft sticks, so his final count becomes (x + 2y) craft sticks.
6. Linda also receives 2y craft sticks, so her final count becomes (x + 2y + 2y) = (x + 4y) craft sticks.
Therefore, in the end, Mark would have (x + 2y) craft sticks, and Linda would have (x + 4y) craft sticks.