a particular cell has half as much dna as some of the other cells in a mitotically active tissue. the in the question is most likely in
anaphase
G1
prophase
metaphase
G2
G1
anaphase
The question is most likely in anaphase.
During anaphase of mitosis, the replicated chromosomes are separated and pulled towards opposite poles of the cell. Each resulting daughter cell will receive a copy of each chromosome. Therefore, if a particular cell has half as much DNA as some of the other cells in a mitotically active tissue, it suggests that this cell is in anaphase, as it has already undergone DNA replication and is now separating the replicated chromosomes.
The question is asking about the phase of the cell cycle in which the particular cell has half as much DNA as some of the other cells in a mitotically active tissue. To determine the answer, let's analyze the different phases mentioned in the options:
1. Anaphase: Anaphase is the phase in which sister chromatids separate and move towards opposite poles of the cell. It does not involve any changes in the amount of DNA.
2. G1: G1 (Gap 1) is the phase before DNA replication occurs. Cells in G1 have a normal amount of DNA.
3. Prophase: Prophase is the phase in which the nuclear membrane breaks down, and chromatin condenses into visible chromosomes. DNA replication has already occurred in this phase, so the amount of DNA in a cell is the same as other cells.
4. Metaphase: Metaphase is the phase in which the chromosomes align at the cell's equatorial plane. Again, there is no change in the amount of DNA.
5. G2: G2 (Gap 2) is the phase after DNA replication but before the cell division. Cells in G2 have twice the amount of DNA compared to G1 cells.
Based on our analysis, the phase that matches the given information is the G1 phase. The particular cell has half as much DNA as some of the other cells in a mitotically active tissue, which suggests that the cell is in G1, where DNA replication hasn't occurred yet.