a solution is prepared by mixing 50.0 mL toluene (C6H5CH3 d=0.867 g/mL) with 125 mL Benzene (C6H6 d=0.874 g/mL). assuming that the volumes add upon mixing, calculate the mass percent, mole fraction, molality, and molarity of the toluene.
Answered below.
2.5%;0.43M;0.44molal,X=7.8×10^3
To calculate the mass percent, mole fraction, molality, and molarity of toluene in the solution, we need to know the masses of toluene and benzene in the mixture.
First, let's calculate the mass of toluene:
Mass of toluene = Volume of toluene x Density of toluene
Mass of toluene = 50.0 mL x 0.867 g/mL
Next, let's calculate the mass of benzene:
Mass of benzene = Volume of benzene x Density of benzene
Mass of benzene = 125 mL x 0.874 g/mL
Now that we have the masses of both components, we can calculate the mass percent of toluene:
Mass Percent of toluene = (Mass of toluene / Total mass of solution) x 100
Total mass of solution = Mass of toluene + Mass of benzene
To calculate the mole fraction of toluene, we need to convert the masses of toluene and benzene into moles:
Moles of toluene = Mass of toluene / Molar mass of toluene
Moles of benzene = Mass of benzene / Molar mass of benzene
Next, we calculate the mole fraction of toluene:
Mole Fraction of toluene = Moles of toluene / (Moles of toluene + Moles of benzene)
To calculate the molarity and molality of toluene, we need to know the molecular weight of toluene and the mass of the solvent (benzene) in kilograms.
Finally, we can calculate the molality and molarity of toluene:
Molality of toluene = Moles of toluene / Mass of benzene (in kg)
Molarity of toluene = Moles of toluene / Volume of solution (in L)
I will calculate these values for you.