write an addition problem with 3 addends in which you regroup once to solve.
You try it.
Write each array as an addition problem and solve
To create an addition problem with 3 addends in which regrouping is required, we will choose numbers carefully. Let's say we have:
15 + 8 + 9
Now, let's solve the problem step by step, regrouping once:
First, add the ones place: 5 + 8 + 9 = 22
Since 22 is greater than 10, we need to regroup.
Regrouping involves carrying the extra ones into the next column (tens column in this case) while keeping the remainder in the current column.
So, we put down the 2 in the ones column, and carry the 10 (or the 1 ten) to the tens column:
1
15
+ 8
+ 9
-----
22
In the tens column, we add the carried 10 with the numbers in the column:
1 + 1 + 0 = 2
Since 2 is less than 10, there is no need to regroup again.
Therefore, the final answer to the addition problem is:
15 + 8 + 9 = 22