Bosnian, I really could use your help on one other problem. I have been working on it and what helps is that you show the steps. Solve using the elimination
method. 5x - 7y = -16, 2x + 8y = 26
Thanks so much for your help
multiply the first equation by 8, the second by 7
40x-56y=-128
14x+56y=182
then add the equations
54x=54
x=1
Now, elimination for solving x
multiply the first equation by 2, and the second by 5
10x-14y=-32
10x+40y=130
subtract the second equation from the first
-54y=-162
y=3
Of course, I'd be happy to help you with solving the system of equations using the elimination method!
Step 1: Start by multiplying one or both equations by a constant to create coefficients for either x or y that will cancel each other out when added or subtracted.
In this case, we can eliminate y by multiplying the first equation by 8 and the second equation by 7:
8 * (5x - 7y) = 8 * (-16) => 40x - 56y = -128 (Equation 1)
7 * (2x + 8y) = 7 * 26 => 14x + 56y = 182 (Equation 2)
Step 2: Now, add or subtract the two equations to eliminate one of the variables. In this case, by adding Equation 1 and Equation 2, we can eliminate y:
(40x - 56y) + (14x + 56y) = -128 + 182
54x = 54
Step 3: Solve for x by dividing both sides of the equation by 54:
54x / 54 = 54 / 54
x = 1
Step 4: Substitute the value of x back into one of the original equations to solve for y. Let's use the first equation:
5(1) - 7y = -16
5 - 7y = -16
-7y = -16 - 5
-7y = -21
Step 5: Solve for y by dividing both sides of the equation by -7:
-7y / -7 = -21 / -7
y = 3
Therefore, the solution to the system of equations is x = 1 and y = 3.
I hope this explanation was clear and helpful! Feel free to ask if you have any further questions.