Calculate the moment of inertia of a uniform disc of mass 200g and radius 5cm about an axis passing through its edge and perpendicular to its plane?

I think you can find the formula you want here

http://www.livephysics.com/physical-constants/mechanics-pc/moment-inertia-uniform-objects/

so you can check your derivation.

To calculate the moment of inertia of a uniform disc, we can use the formula:

I = (1/2) * m * r^2

Where:
I = moment of inertia
m = mass of the disc
r = radius of the disc

Given:
m = 200g = 0.2kg
r = 5cm = 0.05m

Substituting these values into the formula, we have:

I = (1/2) * 0.2kg * (0.05m)^2

Simplifying,

I = 0.01 kg.m^2

Therefore, the moment of inertia of the uniform disc is 0.01 kg.m^2.

To calculate the moment of inertia of a uniform disc about an axis passing through its edge and perpendicular to its plane, we can use the formula:

I = (1/2) * m * r^2

where I is the moment of inertia, m is the mass of the disc, and r is the radius of the disc.

First, we need to convert the mass to kilograms, since the SI unit of mass is kilograms. 200g is equal to 0.2kg.

Next, we need to convert the radius to meters, since the SI unit of length is meters. 5cm is equal to 0.05m.

Now we can substitute these values into the formula:

I = (1/2) * 0.2kg * (0.05m)^2

Simplifying:

I = (1/2) * 0.2kg * 0.0025m^2

I = 0.00025 kg·m^2

So, the moment of inertia of the uniform disc about an axis passing through its edge and perpendicular to its plane is 0.00025 kg·m^2.