physics

A ball is thrown horizontally from the top of a building 43.4 m high. The ball strikes the ground at a point 57.3 m from the base of the building.
The acceleration of gravity is 9.8 m/s^2.
a. Find the time the ball is in motion.
Answer in units of s.
b. Find the initial velocity of the ball. Answer in units of m/s.
c. Find the x component of its velocity just before it strikes the ground. Answer in units of m/s.
d. Find the y component of its velocity just before it strikes the ground. Answer in units of m/s.

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  1. a. h = 0.5g*t^2
    h = 43.4 m.
    g = 9.8 m/s^2
    t = Fall time.
    Solve for t.

    b. Dx = Xo * t
    Dx = 57.3 m. = Hor. dist.
    Xo = Initial hor velocity.
    t = Fall time calculated in part a.
    Solve for Xo.

    c. X = Xo=Initial hor velocity(part b).
    Xo does not change.

    d. Y = Yo + g*t
    Yo = 0
    g = 9.8 m/s^2
    t = Fall time calculated in part a.
    Solve for Y.

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