A block and tackle with a velocity ratio of 5 is used to raise a mass of 25kg through a vertical distances of 40cm at a steady rate.if the effort is equal to 60N,determine.(a)The distance moved by the effort.(b)The workdone by the effort in lifting the load.(c)The loss in energy involve in operating the machine.

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  1. If the block moves .40 meters then the line is pulled 5 * .4 = 2 meters (a)

    the work done by the puller person on that line is
    W in = 60 N * 2 meters = 120 Joules (b)

    the useful work done on the block was to lift it .40 meters
    work out = m g h = 25 * 9.81 * .4 = 98.1 Joules
    so the loss due to friction was
    120 - 98.1 = 21.9 Joules (c)

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