the speed of an object at the end of 4 successive seconds is 20,25,30 and 35 meters per second,respectively.the acceleration of this object is?
acceleration= change in velocity/time
looks like 5m/s /secon= 5m/s^2
Good
Entry test physics
To find the acceleration of an object, you need to use the equation relating acceleration, initial velocity, final velocity, and time:
acceleration = (change in velocity) / time
In this case, we have the final velocities at the end of 4 successive seconds: 20 m/s, 25 m/s, 30 m/s, and 35 m/s. Since the question doesn't provide information about the initial velocity, we'll assume the initial velocity is 0 m/s.
To find the acceleration for each 1-second interval, we can use the formula for change in velocity:
change in velocity = final velocity - initial velocity
For the first interval, the change in velocity is:
change in velocity = 20 m/s - 0 m/s = 20 m/s
Since this change occurred over a time interval of 1 second, the acceleration for the first interval is:
acceleration = (change in velocity) / time = 20 m/s / 1 s = 20 m/s^2
For the second interval, the change in velocity is:
change in velocity = 25 m/s - 20 m/s = 5 m/s
Since this change occurred over a time interval of 1 second, the acceleration for the second interval is:
acceleration = (change in velocity) / time = 5 m/s / 1 s = 5 m/s^2
Similarly, for the third interval:
acceleration = (change in velocity) / time = (30 m/s - 25 m/s) / 1 s = 5 m/s^2
And for the fourth interval:
acceleration = (change in velocity) / time = (35 m/s - 30 m/s) / 1 s = 5 m/s^2
So, for each successive 1-second interval, the acceleration of the object is 5 m/s^2.