a ball of weight 200 grams,is tied to the end of a cord and whirled in a horizontal circle of radius 0.6 m.if the ball makes five complete revolutions in 2 seconds,what will be the linear speed of the ball?
speed=distance/time= 5*2PI*radiius/timetotal
4.42m\s
To find the linear speed of the ball, we need to determine both the circumference of the circle and the time it takes to complete one revolution.
First, let's find the circumference of the circle. The circumference is equal to the diameter multiplied by pi (π). Since the radius is given (0.6 m), we can use this formula:
Circumference = 2 * π * radius
Circumference = 2 * π * 0.6
Circumference = 3.14 * 0.6 * 2
Circumference ≈ 3.76 meters
Now, let's find the time taken to complete one revolution. The problem states that the ball makes five complete revolutions in 2 seconds. Therefore, we can determine the time to complete one revolution by dividing the total time by the number of revolutions:
Time for one revolution = Total time / Number of revolutions
Time for one revolution = 2 seconds / 5
Time for one revolution = 0.4 seconds
Finally, we can calculate the linear speed of the ball using the formula:
Linear speed = Circumference / Time for one revolution
Linear speed = 3.76 meters / 0.4 seconds
Linear speed ≈ 9.4 meters per second
Therefore, the linear speed of the ball is approximately 9.4 meters per second.