Consider the following reaction:
CaCO3(s) --> CaO(s) + CO2(g)
A mixture of calcium oxide (CaO) and calcium carbonate (CaCO3) had a mass of 15.08 g and was heated to above 840 oC. After heating, 9.83 g of solid was left. What is the mass percentage of CaCO3(s) in the original mixture?
CaCO3(s) --> CaO(s) + CO2(g)
initial mass = 15.08g
final mass...= 9.83
mass CO2 lost = 15.08-9.83 = ?
Convert mass CO2 to mass CaCO3 using the coefficients in the balanced equation.
%CaCO3 = (mass CaCO3/mass sample)*100 = ?
To find the mass percentage of CaCO3 in the original mixture, you need to compare the mass of CaCO3 with the mass of the original mixture.
First, let's calculate the mass of CaCO3 in the original mixture by subtracting the mass of the remaining solid (CaO) from the mass of the original mixture.
Mass of CaCO3 = Mass of original mixture - Mass of remaining solid
Mass of CaCO3 = 15.08 g - 9.83 g
Mass of CaCO3 = 5.25 g
Now, we can calculate the mass percentage of CaCO3 in the original mixture using the formula:
Mass Percentage = (Mass of CaCO3 / Mass of original mixture) x 100
Substituting the values:
Mass Percentage = (5.25 g / 15.08 g) x 100
Mass Percentage ≈ 34.8%
Therefore, the mass percentage of CaCO3 in the original mixture is approximately 34.8%.