Physics

A ball is thrown straight upward and returns
to the thrower’s hand after 2.3 s in the air. A
second ball is thrown at an angle of 60◦ with
the horizontal.
At what speed must the second ball be
thrown so that it reaches the same maximum
height as the first? The acceleration of gravity
is 9.8 m/s
2
.
Answer in units of m/s

  1. 👍 0
  2. 👎 0
  3. 👁 533
  1. 2.3/2 = 1.15 seconds to go up

    0 = Vi -4.9 t = Vi - 4.9*1.15
    Vi = 5.365 m/s initial speed up

    the second ball must have same initial vertical component of velocity = 5.365 m/s

    Vi sin 60 = 5.365
    so
    Vi = 6.51 m/s

    1. 👍 0
    2. 👎 1

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