Physics

A bullet is fired vertically upward with an initial velocity of 98m/s from the top of a building 100m high, find a) the maximum height reached above the ground b) the total time before reaching the ground. C) the velocity on landing.

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  1. a. h=ho + (-Vo^2/2g)=100 + (-98^2)/-19.6
    = 590 m.

    b. V = Vo + g*Tr = 0
    98 - 9.8*Tr = 0
    -9.8Tr = -98
    Tr = 10 s. = Rise time.

    h = 0.5g*t^2 = 590
    4.9*t^2 = 590
    t^2 = 120.4
    Tf = 11 s. = Fall time.

    Tr+Tf = 10 + 11 = 21 s. = Time to reach
    gnd.

    c. V^2 = Vo^2 + 2g*h
    Vo = 0
    g = 9.8 m/s^2
    h = 590 m.
    Solve for V.

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