a horizontal force of 3 N is excerted on an object while a vertical force of 4 N is excerted at the same time. calculate the resultant force on the object?
3 square + 4 square = 25
so the resultant force will be 25 N
R=sqrt(3^2 + 4^2)
=sqrt(9+16)
=sqrt(25)
=5 N.
the two vertical and horizontal forces are basically components of the resultant. Good luck in your studies!
Yes
To calculate the resultant force on the object, you can use the Pythagorean theorem, which states that in a right triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
In this case, the horizontal force is represented by one side of the triangle with a magnitude of 3 N, and the vertical force is represented by the other side with a magnitude of 4 N.
Applying the formula:
Resultant force = √(horizontal force^2 + vertical force^2)
= √(3^2 + 4^2)
= √(9 + 16)
= √25
= 5 N
Therefore, the resultant force on the object is 5 N.