Determine the equation of the normal line y=x^2+5 at the point (2, 9)
I got y= 4x+1
dy/dx = 2 x
so -1/slope = -1/2x = -1/4
y = -x/4 + b
9 = -1/2 + b
b = 9.5
y = -x/4 + 9.5
4 y = -x + 38
I got y= 4x+1
so -1/slope = -1/2x = -1/4
y = -x/4 + b
9 = -1/2 + b
b = 9.5
y = -x/4 + 9.5
4 y = -x + 38