rick has a box of coins. The box contains 51 coins. Which consist of pennies, dimes and quarters. The number of pennies equal the number of dimes the total value of the box of coins is 5.73. How many dimes? how many pennies ?

how many quarters?

There are 15 quarters, 18 dimes, and 18 pennies.

15 quarters = 3.75
18 dimes = 1.80
18 pennies = 0.18

3.75 + 1.80 + 0.18 = 5.73

I hope this helps! :)

To find the number of dimes, pennies, and quarters in Rick's box of coins, we can set up a system of equations based on the given information.

Let's assume that Rick has x pennies, x dimes, and y quarters.

Based on the information given:
1) "The box contains 51 coins" - We can write the equation:
x + x + y = 51

2) "The number of pennies equals the number of dimes" - We can write the equation:
x = x

3) "The total value of the box of coins is $5.73" - We know that the value of each penny is $0.01, each dime is $0.10, and each quarter is $0.25. Using this information, we can write the equation:
0.01x + 0.10x + 0.25y = 5.73

Now, let's solve this system of equations to find the values of x (number of pennies), x (number of dimes), and y (number of quarters).

From equation 1), we have:
2x + y = 51

From equation 2), we have:
x = x

Combining these two equations, we get:
x = 51 - y/2

Substituting this value of x into equation 3), we have:
0.01(51 - y/2) + 0.10(51 - y/2) + 0.25y = 5.73

Now, we can solve this equation for y to find the number of quarters.

0.51 - 0.005y + 5.1 - 0.05y + 0.25y = 5.73
Combining like terms:
5.61 - 0.005y + 0.20y = 5.73
0.195y = 0.12
y ≈ 0.615

Since the number of coins must be a whole number, we can round y to the nearest whole number, which is 1.

So, the number of quarters (y) is 1.

Now, substituting y = 1 into equation 1), we get:
2x + 1 = 51
2x = 50
x = 25

Therefore, the number of dimes (x) is 25 and the number of pennies (x) is also 25.

To summarize, there are 25 dimes, 25 pennies, and 1 quarter in Rick's box of 51 coins.