How can i explain hw i can prepare a 250ml of2.5M of HCl acid from;molecular weight of acid 36.5g\mole;density of acid 1.19g\ml and degree of purity of acid 37%

Here is the problem stated differently.

You have a solution of 37% HCl, density 1.19 g/mL. You want to use this solution to prepare 250 mL of 2.5 M HCl.

First determine the molarity of the concentrated HCl (the 37% material).
1.19 g/mL x 1000 mL x 0.37 x (1/36.5) = approximately 12 M but you should do that more accurately.
Then use c1v1 = c2v2
12M x v1 = 2.5M x 250 mL
Solve for V1. Place V1 mL of the 37% material into a 250 mL volumetric flask and add water to the mark on the flask. Mix thoroughly and copper. The resulting 250 mL will be 2.50 M HCl.

To prepare a 250 mL of 2.5 M HCl acid solution, you need to consider the molecular weight of the acid, the density of the acid, and the degree of purity of the acid. Here's how you can calculate it:

Step 1: Determine the amount of acid needed
To calculate the amount of acid needed, we first need to calculate the number of moles required. Since we want a 2.5 M solution, we can use the formula:

moles of acid = volume of solution (in liters) * molarity (M)

First, convert the volume of the solution to liters:
250 mL = 250/1000 = 0.25 L

Now, calculate the moles of acid needed:
moles of acid = 0.25 L * 2.5 mol/L = 0.625 moles

Step 2: Calculate the mass of the acid
To calculate the mass of the acid required, we need to know its molecular weight, which is given as 36.5 g/mol. The formula to calculate the mass of the acid is:

mass = moles of acid * molecular weight

mass = 0.625 moles * 36.5 g/mol = 22.8125 g

Step 3: Adjust for the degree of purity
Since the degree of purity of the acid is given as 37%, we need to adjust the mass of the acid required. Multiply the calculated mass by the purity percentage (expressed as a decimal):

adjusted mass = mass * (purity/100)

adjusted mass = 22.8125 g * (37/100) = 8.446875 g

Step 4: Calculate the volume of the acid solution
The density of the acid solution is given as 1.19 g/mL. To calculate the volume of the acid needed to obtain the desired mass, use the formula:

volume = mass / density

volume = 8.446875 g / 1.19 g/mL = 7.10756 mL

Therefore, to prepare a 250 mL of 2.5 M HCl acid solution with a molecular weight of 36.5 g/mol, a density of 1.19 g/mL, and a degree of purity of 37%, you would need to measure approximately 7.11 mL of the acid.