In which quadrant does the solution ofthen system fall?
y=x-1
y= -3x-5
I forgot my answer which is quadrant III.
x-1 = -3x -5
4 x = -6
x = -1.5
y also negative
yes quad three
Yes, it goes in the third quadrant ( III )
To determine the quadrant in which the solution of the system falls, we need to find the values of x and y that satisfy both equations. Let's solve the system of equations step by step.
The given system of equations is:
1) y = x - 1
2) y = -3x - 5
To solve this system, we can substitute equation 1) into equation 2) for y:
-3x - 5 = x - 1
Simplifying this equation, we get:
-4x - 5 = -1
Next, let's solve for x:
-4x = -1 + 5
-4x = 4
x = 4 / -4
x = -1
Now that we have the value of x, we can substitute it back into equation 1) to find y:
y = (-1) - 1
y = -2
Therefore, the solution of the system is x = -1 and y = -2.
To determine the quadrant in which this point falls, we need to consider the signs of x and y.
In the x-y coordinate plane, the quadrants are numbered as follows:
^ y
|
II | I
_________|_________> x
|
III | IV
|
Since x = -1 (negative) and y = -2 (negative), the point (-1, -2) falls in the third quadrant.