the second floor of a house is 6m above street level. How much work is required to lift a 300-kg refrigerator to the second-floor level?
300 * 9.81 * 6 Joules
300kg/6m = 50N
To calculate the work required to lift the refrigerator to the second floor, we can use the formula:
Work = Force × Distance
First, let's calculate the force required to lift the refrigerator. The force needed is equal to the weight of the refrigerator, which can be calculated using the formula:
Force = mass × acceleration due to gravity
Acceleration due to gravity is approximately 9.8 m/s².
Force = 300 kg × 9.8 m/s² = 2940 N
Now, let's calculate the distance the refrigerator needs to be lifted. You mentioned that the second floor is 6 m above street level.
Distance = 6 m
Now we can calculate the work required:
Work = Force × Distance
Work = 2940 N × 6 m = 17,640 Joules
Therefore, it would take 17,640 Joules of work to lift the 300 kg refrigerator to the second floor.
To determine the amount of work required to lift a 300-kg refrigerator to the second-floor level, we need to use the formula for the work done against gravity:
Work = Force × Distance
In this case, the force is the weight of the refrigerator, which can be calculated using the formula:
Force = mass × gravitational acceleration
The standard gravitational acceleration is approximately 9.8 m/s².
Let's plug in the values:
Mass = 300 kg
Gravitational acceleration = 9.8 m/s²
Force = 300 kg × 9.8 m/s² = 2940 N
Now, we need to calculate the distance. The problem states that the second floor is 6m above the street level, so the distance is 6m.
Work = Force × Distance = 2940 N × 6 m = 17,640 joules
Therefore, it would require approximately 17,640 joules of work to lift a 300-kg refrigerator to the second-floor level.