Jared has a bag that contains 8 blue marbles, 6 red marbles, and 10 green marbles. He selects a marble, replaces it in the bag, and then selects another marble. What is the probability that both marbles are green
prob = (10/24(10/24) = 25/144
To find the probability that both marbles Jared selects are green, we need to calculate the likelihood of selecting a green marble on the first draw and then another green marble on the second draw.
First, let's determine the probability of drawing a green marble on the first draw.
Jared has a total of 8 + 6 + 10 = 24 marbles in his bag, and 10 of them are green. So, the probability of drawing a green marble on the first draw is 10/24 or 5/12.
Since Jared replaces the marble back into the bag before drawing again, the probability of drawing another green marble on the second draw is also 10/24 or 5/12.
To find the probability of both events happening, we multiply the individual probabilities. So the probability that both marbles are green is (5/12) * (5/12) = 25/144.
Therefore, the probability that both marbles Jared selects are green is 25/144.