(iii) If the chemist wants to prepare 5.00 litres of the stock solution from concentrated H2SO4 , which is 18.0M, what volume of concentrated acid should be used?
It all depends upon what concentration the chemist wants the stock solution. If we call that M, it will be
c1v1 = c2v2
M*5.00L = 18M x v2
substitute M from your problem, which you didn't post, and solve for v2 of the 18.0 M.
To determine the volume of concentrated H2SO4 required to prepare 5.00 liters of a stock solution with a concentration of 18.0M, we can use the equation:
(C1)(V1) = (C2)(V2)
Where:
C1 = Concentration of concentrated H2SO4
V1 = Volume of concentrated H2SO4
C2 = Concentration of stock solution
V2 = Volume of stock solution
Now, we can substitute the given values into the equation:
(18.0M)(V1) = (5.00L)(18.0M)
Simplifying the equation, we have:
V1 = (5.00L)(18.0M) / (18.0M)
V1 = 5.00L
Therefore, the volume of concentrated H2SO4 required to prepare 5.00 liters of the stock solution is 5.00 liters.
To determine the volume of concentrated acid required to prepare the stock solution, we can use the formula:
M1V1 = M2V2
where M1 represents the concentration of the concentrated acid, V1 represents the volume of the concentrated acid, M2 represents the desired concentration of the stock solution, and V2 represents the desired volume of the stock solution.
Given:
M1 = 18.0 M (concentration of concentrated H2SO4)
V2 = 5.00 L (desired volume of the stock solution)
M2 = ?
Rearranging the formula:
V1 = (M2 * V2) / M1
Plugging in the given values:
V1 = (M2 * 5.00 L) / 18.0 M
To find the volume of concentrated acid required, we need to know the desired concentration of the stock solution (M2). Please provide that information.