If 0.50 mol of Na3PO4 is mixed with 0.30 mol
of BaCl2, the maximum number of moles of barium
phosphate which can be formed is:
How do i set up the problem?
you need the balanced equation:
2Na3PO4 + 3BaCl2 --> Ba3(PO4)2 + 6NaCl
So, each 2 moles of Na3PO4 yields 1 mole of Ba3(PO4)2
To determine the maximum number of moles of barium phosphate that can be formed, we need to find the limiting reactant in the given reaction. The limiting reactant is the one that will be completely consumed and determines the amount of product formed.
1. Write the balanced chemical equation for the reaction:
3Na3PO4 + 2BaCl2 -> Ba3(PO4)2 + 6NaCl
2. Calculate the number of moles for each reactant given:
0.50 mol Na3PO4
0.30 mol BaCl2
3. Use the balanced equation to determine the mole ratio between Na3PO4 and Ba3(PO4)2:
According to the balanced equation, 3 moles of Na3PO4 react with 2 moles of BaCl2 to produce 1 mole of Ba3(PO4)2.
4. Calculate the number of moles of Ba3(PO4)2 predicted by each reactant:
For Na3PO4: (0.50 mol Na3PO4) x (1 mol Ba3(PO4)2 / 3 mol Na3PO4) = 0.167 mol Ba3(PO4)2
For BaCl2: (0.30 mol BaCl2) x (1 mol Ba3(PO4)2 / 2 mol BaCl2) = 0.150 mol Ba3(PO4)2
5. Compare the calculated moles from step 4 and identify the limiting reactant:
In this case, the limiting reactant is BaCl2 since it produces fewer moles of Ba3(PO4)2 compared to Na3PO4.
6. The maximum number of moles of barium phosphate that can be formed is 0.150 mol.
To set up the problem, you need to determine the balanced chemical equation for the reaction between sodium phosphate (Na3PO4) and barium chloride (BaCl2). The balanced equation is:
3Na3PO4 + 2BaCl2 → Ba3(PO4)2 + 6NaCl
From the balanced equation, you can see that the ratio of Na3PO4 to Ba3(PO4)2 is 3:1. This means that for every 3 moles of Na3PO4 reacted, 1 mole of Ba3(PO4)2 is produced.
In this problem, you have 0.50 mol of Na3PO4 and 0.30 mol of BaCl2. To find the maximum number of moles of barium phosphate (Ba3(PO4)2) that can be formed, you need to determine which reactant is limiting. The limiting reactant is the one that is completely consumed first and determines the amount of product formed.
To determine the limiting reactant, compare the moles of each reactant to the stoichiometric ratio in the balanced equation.
For Na3PO4:
0.50 mol Na3PO4 x (1 mol Ba3(PO4)2 / 3 mol Na3PO4) = 0.17 mol Ba3(PO4)2
For BaCl2:
0.30 mol BaCl2 x (1 mol Ba3(PO4)2 / 2 mol BaCl2) = 0.15 mol Ba3(PO4)2
Since the ratio of Na3PO4 to Ba3(PO4)2 is 3:1, and you have less moles of Ba3(PO4)2 from BaCl2 (0.15 mol) compared to Na3PO4 (0.17 mol), the limiting reactant is BaCl2.
Therefore, the maximum number of moles of barium phosphate that can be formed is 0.15 mol.