Ask questions and get helpful responses.
Ask a New Question
  1. Questions

Calculus (math)

The velocity function (in meters per second) for a particle moving along a line is given by v(t)=t3−5t2. Find the displacement and the distance traveled by the particle during the time interval [-1,6].

Distance traveled = ??

I got 2089/12m as answer but it was incorrect please help me!

  1. 👍
  2. 👎
  3. 👁
  4. ℹ️
  5. 🚩
Help me plz!

  1. s(t) = 1/4 t^3 - 5/3 t^3 + c
    The displacement is s(6)-s(-1)

    The distance traveled is the arc length. So, what steps did you follow?

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
    Steve

  2. if v(t) = t^3 - 5t^2
    s(t) = (1/4)t^4 - (5/3)t^3 + c

    s(6) = (1/4)6^4 - (5/3)6^3 = -36 + c
    s(-1) = (1/4)(-1)^4 - (5/3)(-1)^3 = 23/12 + c

    distance traveled = 23/12+c - (-36+c) = 4550/12

    1. 👍
    2. 👎
    3. ℹ️
    4. 🚩
    Reiny

Respond to this Question

First Name

Your Response

Similar Questions

  1. Calculus

    The velocity function (in meters per second) is given for a particle moving along a line. v(t) = 3t − 7, 0 ≤ t ≤ 3 (a) Find the displacement. -7.5 m (b) Find the distance traveled by the particle during the given time

  2. Calculus

    The displacement (in centimeters) of a particle s moving back and forth along a straight line is given by the equation s = 3 sin(𝜋t) + 3 cos(𝜋t), where t is measured in seconds. (Round your answers to two decimal places.)

  3. Calc 1

    The acceleration function (in m/s2) and the initial velocity v(0) are given for a particle moving along a line. a(t) = 2t + 2, v(0) = −3, 0 ≤ t ≤ 4 (a) Find the velocity at time t. (b) Find the distance traveled during the

  4. calculus

    5. A particle moves along the y – axis with velocity given by v(t)=tsine(t^2) for t>=0 . a. In which direction (up or down) is the particle moving at time t = 1.5? Why? b. Find the acceleration of the particle at time t= 1.5. Is

  1. Calculus

    A particle moves along the x-axis so that it’s position s in meters at any time t>0 in seconds is given by the function s(t)=2t+2sin((pi/2)t). A. Find the velocity of the particle, and then determine the velocity at times t=1

  2. Calculus (Derivatives)

    Two particles are moving in straight lines. The displacement (in meters) of particle 1 is given by the function e^(4cos(t)) , where t is in seconds. The displacement (in meters) of particle 2 is given by the function -(t^3)/(3) -

  3. calculus

    The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s = 2 sin(πt) + 2 cos(πt), where t is measured in seconds. (Round your answers to two decimal

  4. Calculus

    The velocity function is v(t)=t^2-5t+6 for a particle moving along a line. Find the displacement of the particle during the time interval [-3,6].

  1. calc

    The velocity function, in feet per second, is given for a particle moving along a straight line. v(t) = t3 − 10t2 + 27t − 18, 1 ≤ t ≤ 7 Find the displacement Find the total distance that the particle travels over the given

  2. physics

    A particle moves in a circle in such a way that the x- and y-coordinates of its motion are given in meters as functions of time t in seconds by: x=5cos(3t) y=5sin(3t) What is the period of revolution of the particle? Here's what

  3. Calculus..

    Two particles are moving in straight lines. The displacement (meters) of particle 1 is given by the function s(t)= cos(4x), where t is in seconds. The displacement (meters) of particle 2 is given by the function s(t)= t^3/3-t^2/2

  4. calculus homework help stuck

    Let s(t) denote the position of a particle at time t, and let v and a be the velocity and acceleration respectively. The particle is moving according to the data a(t)=10sin(t)+3cos(t) s(0)=-4 s(2pi)=1 find a function describing

Still need help? You can ask a new question.