In four non collinear points , how many line segments can be drawn?

6 segments can be drawn. You can draw a figure to figure it out.

In a set of four non-collinear points, you can draw line segments between each pair of points. To calculate the total number of line segments, you can use the formula for combinations: nC2, where n is the number of points. In this case, n = 4.

Using the formula, we have:

4C2 = (4!)/(2!(4-2)!) = (4*3)/(2*1) = 6.

Therefore, you can draw 6 line segments between the four non-collinear points.

To find the answer to this question, we need to understand how to calculate the number of line segments that can be drawn between four non-collinear points.

In this case, we have four points that are not in a straight line (non-collinear):

Let's say the four points are A, B, C, and D.

To determine the number of line segments that can be drawn, we need to consider each possible pair of points and calculate the number of line segments between them.

Using the combination formula, we can determine the number of line segments. In this case, we need to calculate the combinations of 4 objects taken 2 at a time.

The formula for combinations is:

nCr = n! / (r! * (n-r)!)

Where n is the total number of objects, and r is the number of objects taken at a time.

In this case, n = 4 and r = 2:

4C2 = 4! / (2! * (4-2)!) = 4! / (2! * 2!) = (4 * 3 * 2 * 1) / ((2 * 1) * (2 * 1)) = 6.

Therefore, there are six line segments that can be drawn between the four non-collinear points.

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the number of segments determined by n points is

and you will find many discussions of the topic. Find the one you like and use n=4.