how much heat is required to raise a 54g sample of water from -20 celsius to 90 celsius
explain
IS IT POSSIBLE IF YOU CAN DO THIS ONE FOR ME SO I CAN DO THE REST ON MY OWN SO I HAVE A IDEA OF WHAT TO DO AND WILL BE EASIER TO UNDERSTAND
To determine the amount of heat required to raise the temperature of a substance, you can use the equation:
Q = m * c * ΔT
Where:
Q is the amount of heat energy
m is the mass of the substance
c is the specific heat capacity
ΔT is the change in temperature
In this case, you have a 54g sample of water, so m = 54g.
The specific heat capacity of water is approximately 4.18 Joules per gram per degree Celsius (J/g°C), which we will use for c.
ΔT is the change in temperature, which in this case is from -20°C to 90°C. Therefore, ΔT = 90°C - (-20°C) = 110°C.
Now, we can substitute the values into the equation to calculate the amount of heat energy required:
Q = (54g) * (4.18 J/g°C) * (110°C)
By performing the calculation, we can find the answer:
Q = 25588.4 Joules
Therefore, it would require approximately 25588.4 Joules of heat energy to raise a 54g sample of water from -20°C to 90°C.
To calculate the amount of heat required to raise the temperature of a substance, you can make use of the specific heat capacity formula:
Q = m * c * ΔT
Where:
Q = heat energy (in joules)
m = mass of the substance (in grams)
c = specific heat capacity of the substance (in J/g°C)
ΔT = change in temperature (in °C)
In this case, you have a sample of water weighing 54 grams and you want to raise its temperature from -20°C to 90°C.
First, let's calculate ΔT:
ΔT = final temperature - initial temperature
ΔT = 90°C - (-20°C)
ΔT = 110°C
Next, we need to determine the specific heat capacity of water. For water, the specific heat capacity is approximately 4.18 J/g°C.
Now, we can substitute the given values into the formula to find the amount of heat energy required (Q):
Q = m * c * ΔT
Q = 54g * 4.18 J/g°C * 110°C
Calculating:
Q ≈ 26,185.2 Joules
Therefore, approximately 26,185.2 Joules of heat energy are required to raise a 54g sample of water from -20°C to 90°C.
q1 = heat to raise T from -20 to zero.
q1 = mass ice x specific heat ice x (Tfinal-Tinitial) where Tf is 0 and Ti is -20.
q2 = heat to convert solid ice at zero to liquid water at zero C.
q2 = mass ice x heat fusion
q3 = heat to raise T of liquid water at zero C to 90 C.
q3 = mass water x specific heat liquid water x (Tfinal-Tinitial)
Total q is sum q1 + q2 + q3.